The n+2 Management Policy

I think this is a decent way to operate in a hierarchy–particularly when it comes to big decisions like hiring/firing/approving new policies.  We first assume the hierarchy is a tree (i.e. each member has only one immediate supervisor) and that there is a maximal element, called an “administrator”.  The setup is that if something happens at level n in the hierarchy (say hiring/firing someone at level n (presuming the action is consistent with other policy)), then the relevant supervisor makes the nomination/recommendation for the action, and his/her supervisor confirms the action.

Hence let H be a tree, x\in H, and S(x) denote the supervisor of x.  Typically in trees, minimal elements are considered level 0.  Here we reverse the ordering and call the maximal element the administrator, denoted by A, and say \mbox{rank}(A)=M.  We define a rank n policy as a policy that affects all successors (subordinates) of an element x\in H such that \mbox{rank}(x)=n.  Hence we have:

The n+2 Operational Policy.  Let P be a rank n policy and x_P denote the member whose subordinates are affected.  The policy then becomes activated provided S(x_P) proposes it and S(S(x_P)) approves it.

Hence the n+2 Operational Policy itself is a rank M policy as it affects everything in the hierarchy.  But we arrive at a problem in continuing to execute this policy at levels M-1 and M.  So we adjoin another set to the hierarchy called the board, denoted B, and redefine our hierarchy as H=T\sqcup B where T denotes the initial tree with unique maximal element A. We then define S(A)=B and S(B)=B.

The main positive of this method is the minimizing of micromanagement.  The only big negative that stands out is the possibility of actions diverging from intentions of a level n member as one goes down the ladder.  But I’d argue that this just means more level n policy needs to be implemented in order to prevent that.

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